(3x^2-4x+7)+(3x-3x^2)+(x-7)=0

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Solution for (3x^2-4x+7)+(3x-3x^2)+(x-7)=0 equation: 


Simplifying
(3x2 + -4x + 7) + (3x + -3x2) + (x + -7) = 0

Reorder the terms:
(7 + -4x + 3x2) + (3x + -3x2) + (x + -7) = 0

Remove parenthesis around (7 + -4x + 3x2)
7 + -4x + 3x2 + (3x + -3x2) + (x + -7) = 0

Remove parenthesis around (3x + -3x2)
7 + -4x + 3x2 + 3x + -3x2 + (x + -7) = 0

Reorder the terms:
7 + -4x + 3x2 + 3x + -3x2 + (-7 + x) = 0

Remove parenthesis around (-7 + x)
7 + -4x + 3x2 + 3x + -3x2 + -7 + x = 0

Reorder the terms:
7 + -7 + -4x + 3x + x + 3x2 + -3x2 = 0

Combine like terms: 7 + -7 = 0
0 + -4x + 3x + x + 3x2 + -3x2 = 0
-4x + 3x + x + 3x2 + -3x2 = 0

Combine like terms: -4x + 3x = -1x
-1x + x + 3x2 + -3x2 = 0

Combine like terms: -1x + x = 0
0 + 3x2 + -3x2 = 0
3x2 + -3x2 = 0

Combine like terms: 3x2 + -3x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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